This will be your final post of the semester. I know you have thoroughly enjoyed typing these blogs this semester. Also I know you have liked working with numerous equations and their graphs. This blog still needs to be at least 4 paragraphs long with at least 4 sentences in each paragraph. This is wworth 20 points and due Wednesday December 7th by class time. Make sure you stop b this blog next Tuesday for a way to earn some extra for your test.
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December 3, 2011 at 2011-12-03T15:46:32+00:00 3:46 pm
Rate of change and slope- To find the rate of change you have to put the dependant varible over the independant. on graphs you do the vertical over the horizontal. One way to find slope is make a triangle between the two points.Another way is use the formula for slope. This was a very easy section
Slope intercept form- This is one of the three formula’s to figure out the line’s equation. What you do is put the slope then put where the line crosses the y-axis. The formula is y=mx+b. All you have to do is plug these things in. This is another easy thing to do.
Standard and point slope form- The formula to standard is Ax+By=C. The formula for pt. slope is y-y1=m(x-x1). You just plug in the numbers like on the other formula. This was very easy.
Overall this chapter was easy except for section 3 it was pretty hard. I hope the final and the next chapter is easy. I thouht I did pretty good on this section overall. Mr. Kutcher you are awesome!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
December 3, 2011 at 2011-12-03T16:06:14+00:00 4:06 pm
Slope is the easiest equation to do. it is y2-y1 over x2-x1…this helps you find the slope on points. You don’t need a graph to find the slope. You use this to find the slope without a graph or if you like it better this way.
Slope intercept is mx + b which is harder for me to understand. But when you have m=-3/4 & 2 is b. This would be y = -3/4x + 2. How you graph it is is you start at 2….then go down 3 because its negative then go right 4. then put a point on that & on 2. Then you have you equation.
Standard form is Ax + By = C. This is kind of confussing for me to understand. But after you get the y alone it is very easy.I wish i you have better understood this part of the section.
This chapter was pretty easy and simple to understand. Other than section 3 and i didn’t understand where you do all 4 steps that is alittle confussing. But not hard for the slope & the pt. slope. Overall i did enjoy this chapter
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December 4, 2011 at 2011-12-04T17:20:57+00:00 5:20 pm
The first thing was rate of change and slope, I thought this was the easiest part of this chapter. All you have to do if you have the points is y2-y1 over x2-x1. You can also do it with the graph, by just taking rise over run. There is also times when you dont have a slope and its just zero, or it can be undefined, depending if its on the x or y axis.
The next section was slope-intercept form, which is where you have the slope and the y-int. The formula is y=mx+b, which I thought was really easy to remember. Next thing was applying linear functions which I thought was kinda hard, and it took forever to do just one problem. I didnt like having to graph all of it either.
Next it was standard form, which I thought was another easy section. This form tells you the x and y coordinates, using the formula Ax+By=C. Then we had point-slope form, which tells you the x and y coordinates and the slope. The formula to this one is y-y1=m(x-x1). Last it was Parallel and perpendicular lines, which were pretty easy. For parallel you have the same slope but different y-int, and perpendicular you have the opposite reciprocal of the slope.
I think this was one of our harder chapters, since you have to remember more formulas. I think I’ve got them most of the way memorised. Hopefully the I do good on the test. I hope the final Isn’t extremely hard so I can end the semester with a good grade.
December 5, 2011 at 2011-12-05T18:01:02+00:00 6:01 pm
Chapter 6 blog
we have been working on the rate of change and slope y=x-7 the slope is 1 the y intercept is the 7 I gets confusing even more when the equation gets bigger we have been doing the equations like m=2/3x +1 are the slope and the y intercept and we also have been learning the applying linear functions witch is a graph that says on one of the sides like a total car and on the bottom they have number of car carriers an equation is y=40+6-x and the we have also been learning the slope intercept form which is not that hard its like y=mx +b the m would be the slope the b would be the y-intercept we have been learning all through the chapter was slope pt-slope form slope intercept parallel lines standard form perpendicular lines vertical and horizontal lines through out this chapter which have all been kind off easy but the standard form to me was difficult.
December 5, 2011 at 2011-12-05T19:38:26+00:00 7:38 pm
This chapter was pretty easy and simple to understand. Other than section 3 and i didn’t understand where you do all 4 steps that is alittle confussing. But not hard for the slope & the pt. slope. All you have to do if you have the points is y2-y1 over x2-x1. All this was hard and the graphing is hard but when u accually tri you get it i had trouble with graphing for awhile i somewhat likes this section of the chapter section 3 was really a challenge but i tried my best :3 i hope that it worked.
December 5, 2011 at 2011-12-05T23:19:53+00:00 11:19 pm
In this chapter we learned how to apply slope, pt slope intercept form, o and i finally found out wat horizantal and vertical lines are. And we also learned wat perpindicular lines and how to graph parallel lines. we also learned about y-y and x-x is a simple way to find the slope. remember rYse over run.
I think i had the most trouble with the perpindicular lines. mainly because i was gone wed thurs and friday. the other hard thing that i thought was the vertical and horizontal lines. i never knew and the found out and it made it a lot easier. the perpindicular stuff was not to hard once i found out how to do that, thanks mr. kutscher.
the other big thing we learned about was the slope intercept form. it was actually pretty hard. i know now you have to go like y-y=m(x-x). the last thing that we learned was the standard form. it was probably the easiest of them all.
overall i think this chapter was decent. it had its up and downs and twists. but if you are ever gone the book can help out pretty well. And so can mr. kutscher if your at school.
December 6, 2011 at 2011-12-06T01:16:21+00:00 1:16 am
In Chapter 6, we learned a lot of new things. One of the first things we learned is slope which is the rate of change in a line. Slope or (m) equals y2 – y1 over x2 -x1. So if i plugged in (2,3) and (1,1) the slope would be 2 because it is -2 over -1 which makes it positive.
Then we learned about linear functions, the y-interecept, and the slope-intercept form of a line. The slope-intercept form of a line is y=mx+b. B equals the initial starting point or, y-intercept. There is also to other forms you can write a linear function which is standard form (Ax+By=C) and point slope form(y-y1=m(x-x1)).
You can also find the slope for a horizontal line and a vertical line. For horizontal line, it is just 0 and for a verticle line, it is a fraction over zero or undifined. Then we talked about parallel and perpendicular lines. The thing about them is that, for a parallel line the slope is the same but the y-intercept is different. For perpendicular lines, the slope has one and the the other slope for the other line is the negative reciprocal of the 1st line.
I thought this chapter had lots of information in it. It was for the most part easy. The easiest for me is finding the slope and doing the y-intercept form of a line. I think I will do well on the test.
December 6, 2011 at 2011-12-06T01:27:33+00:00 1:27 am
This chapter we talked about rate of change, slope, slope int. form, applying linear functions, standard form, point slope form, parallel lines, perpindicular lines. I learned alot in this chapter although we didnt get it all done. The formulas kind of mixed me up though. I am apprehensive about the test because the formulas might be a little hard but I think I got them down.
Rate of change is finding the rate of how much something changes such as there is a whole pop (16 oz.) and Billy drinks half of it in 2 seconds find the rate of change. Well half of 16 is 8 so half of it is gone, we want to get the seconds down to one so you have to take 8 divided by 2 and the rate of change is 4 ounces every 1 second. Slope is kind of like the rate of change but on a graph. The formula to get it is y-y1 over x-x1.
Slope intercept form is the 2nd easiest of the 4 slope formulas. The formula is y= mx+b, m is the slope and b is the y intercept, you need 2 pairs of coordinates and find the slope and the y intercept. The coordinates are (2,-3) and (6,7) and the y int is 5 and the slope is 10 over 4 then you take the y int. and plug it in to the b and the slope for the m, y= 10/4x+5. Standard form is also easy, the formula is Ax+By=C and it NEVER EVER has decimals or fractions. I will use our slope intercept form from earlier to show how to do it. we move the slope and x to the y side so it makes it -10/4x+y=5 then we take out the decimals by multiplying EVERYTHING by the denominator, 4(-10/4+y=5). it turns out to be -10+4y=20 and that is standard form.
This chapter was easy in every sense but the formulas. I hope to get an A or high B. This is the last chapter before finals I think so I want to do really good on it. Thats all I got to say about that.
December 6, 2011 at 2011-12-06T02:45:31+00:00 2:45 am
this chapter had its up and downs. it was easy at times then it got hard and confusing butg then i got it.. now its easy. as long as i have all the equations written down and infront of me. first we talked about rate of change and slope and y intercept. to find the slope u take m=y2-y1 on top of x2-x1. m is your slope.after that we talked about standard form that equation is Ax=By=C. an example is 5x-2y=10. your integers cant be a fraction or a decimal. you always have to graph the 2 points. that wasnt to hard. after that we talked bout horizontal and vertical lines, if its a horizontal line then the equation is y=a(watever the number is). if its a vertical line then the equation is well x=(watevetr the #is).
you can find the slope intercept then go and put it in standard for. its not that hard. all you have to do is get y and x on teh same side then you multiply everything by the denominator. after you do that then thats in standard form and you got the right answer if you distribute right.
you need two things to graph a line:
*1. slope & y-int.
*2. x-int. & y-int.
_3. any 2 pts.
_4. slope and any pt.
for step 4 you have to write an equation in point slope form— y-y1=m(x-x1)
for step 3 you find the slope then do pt. slope form
then we did parallel and perpendicular lines.
paralell lines dont touch. perpend. lines intercect @ a right angle.
for a parallel line to be parallel the slope has to be the same and the y-int. is different. so that means that y=-1/3x+5 and 2x+6y=12 are parallel. for a line to be perpendicular they have opposite recipricals.such as m1= 3/5 and m2= -5/3. you add a negative and flip the fraction. if teh question says to write teh equation parellel to y=(3x-5) an dgoes through the pt. (1,2).this is where you wanna cross out the -5, you dont need it itll just confuse you. you write it in pt. slope form. so -y-2=3(x-1).
when we had to put all these steps we learned together it wasnt as hard as i thought it was going to be. it was really easy. if we get to use our little cheat sheet we made in class then i should be o.k..
i hope i do good on this test on wednesday!! good luck to all test takers!!
December 6, 2011 at 2011-12-06T03:35:29+00:00 3:35 am
In the first lesson we learn about rate of change. Rate of change allows you to see the relationship between two quanities that are changing.So what you do is divide the change in the dependent variable by the change in the independent variable and that is how you get your rate of change. We use this to find it in a graph or in a equation.We also learned about finding the slpoe with using points and the formula is y1-y2 over x1-x2.
In lesson 2 we learned about slope-intercept from. We learned that a linear function is a function that graohs a striaght line. A parent functin is the simplest equation of a function. A linear equation is an equation that maodels a linear function. We learned how to do the poin0slope form with a graoh and a equation also. In lesson 3 we learned how to apply linear functions. This one is the hardest for me because it has story problems in it and those are one of my weaknesses.
In lesson 4 we learned about standard form. The formula for that is Ax+By=C. First you have to find the x and y intersepts. And if you have to you can graph it. But if the equation is not set up right then u have to get the that to the side it needs to be on. In lesson 5 we learned about point-slope form and writing linear equations. The point-slope form of the equation of a nonvertical line that passes through a certian point and has a slope. Then we learnewd about parallel and perpendicular lines. Parellel lines have the same slope but diiferent y-intercept. Perpendicular lines form a upsidedown t which forms a angle.
This chapter was more on the hard side. Its hard because sometimes i forget jhow to do something and it really frustrates me. I know i dont have to remember the formulas but they can trick you every now and then. I hope i do good on the test and the finals.
December 6, 2011 at 2011-12-06T15:18:28+00:00 3:18 pm
Chapter 6 Blog:
Rate of change and slope: rate of change allows you to see the relationship between two quantities that are changing. If one quantity depends on the other then follow the formula, change in the dependent over change in the independent. Slope is a graph of something’s rate of change. To find slope follow the formula ryse over run. The reason ryse is spelled this way is because Y (rYse) is on top in this formula and x goes on the bottom.
Slope-intercept form: linear function is a function that graphs a line. A linear equation is an equation that models a linear function. Y-intercept is the place were the line crosses the y-axis. Slope-intercept form’s formula is y=mx+b.
Standard form: the formula for standard form is Ax+By=C. X intercept is the place were the line touches the x axis. In this equation their can be no fractions only whole numbers and decimals. To graph it hold up your thumb to the to separately at different times to the A and B and then graph the number on the x or y intercept depending on which letter the number is by on that axis.
I thought this chapter was the hardest on all year. And unfortunately this is also the most important thing this year. The hardest was parallel and perpendicular lines. Then Mr. Kutscher explained it to me and I got it a little better
December 6, 2011 at 2011-12-06T15:28:26+00:00 3:28 pm
In 6-1 we learned about rate of change and slope. rate of change is the relationship between two quantities that are changing. if one quantity depends on the other then the rate of change is change in dependent cariable over the change in the independent variable. slope is rise over run or vertical change over horizontal change. the slope of a line is its rate of change.
in 6-2 we learned about linear functions, linear equations and the Y-intercept. the linear function is a function that graphs a line. direct variations are only part of the family of linear functions. a linear equation is an equation that models a linear function. the Y-intercept is the Y-coordinate of the point where a line crosses the Y-axis.
You can also find the slope for a horizontal line and a vertical line. For horizontal line, it is just 0 and for a verticle line, it is a fraction over zero or undifined. Then we talked about parallel and perpendicular lines. The thing about them is that, for a parallel line the slope is the same but the y-intercept is different. For perpendicular lines, the slope has one and the the other slope for the other line is the negative reciprocal of the 1st line.
For parallel you have the same slope but different y-int, and perpendicular you have the opposite reciprocal of the slope.
I think this was one of our harder chapters, since you have to remember more formulas. I think I’ve got them most of the way memorised. Hopefully the I do good on the test. I hope the final Isn’t extremely hard so I can end the semester with a good grade.
December 6, 2011 at 2011-12-06T15:29:34+00:00 3:29 pm
In this chapter we learned about the different equation forms. point slope form has the slope and the different points. It can have more than one points. Ex. y-2=4(x-5).
This chapter also included the slope intercept form. It has the slope and y-intercept. i think this is most useful for graphing. Ex. y=5x+4.
This chapter also told us about the standard form. these equations cant have any fractions or decimals. It includes the x and y intercept. Ex. 3x-4y=12.
This chapter was what i would expect algebra one to be; average. everything was ok but the also came with difficulties like turning one equation to a different form. I think i should do well if i study.
December 6, 2011 at 2011-12-06T15:30:18+00:00 3:30 pm
In this chapter we learned how to find the slope on a graph. If given two points on a coordinate graph, you use the equation y2-y1/x2-x1. the number on top is the y coordinate. the number on bottom is the x coordinate. this is your slope (ryse over run).
In the second lesson we learned about slope intercept form. the formula for this is y=mx+b. m=slope. b=y intercept. if given two points on a graph, you can figure out the slope, then put it in slope intercept form.
In the third lesson we learned about point slope form. the formula for this y-y1=m(x-x1). if given two points, i could find the slope(m). then i would choose a point(x1,y1) and plug those into the formula.
Then we learned about standard form. the formula for this is Ax+By=C. i understood this lesson much better than the last one. i think i will do well on the test.
December 6, 2011 at 2011-12-06T15:33:02+00:00 3:33 pm
Rate of change and slope was what we learned first. Then we learned about slope inercept form. Then we learned about aplying liner functions. Then we learned about standard form. Then point slope form. Then parrellel and perpendicular lines.
rate change is dependant over independent. We learned how to find the slopes of lines. Rise over run. We learned liner functions. We learned what a liner equatiion was. We learned how to find the y intercept. And what the y intrecept was.
We learned what slope intercept form was. y=mx+b. M is the slope and b is the y intercept.we learned how to find the standard form of a lliner equation. Ax+By=C. Where A B and C are real numbers and B and B are not both zero.
Every one is having truble with this chapter. But I think that it was an easy chapter. Im just glad that we dont have to memorise all the equatiions. If we did I probably would fail the test.
December 6, 2011 at 2011-12-06T15:34:13+00:00 3:34 pm
I like this chapter because it was fairly easy but fairly difficult. The paralell lines were kind of hard. I know that the slopes will have to be the same and the y intercept have to be different. Perpendicular lines are intersecting lines that pass through each other.
Slope was EASY. you litteraly cannot mess it up unless you dont know how to subtract. And you can count how many it goes up and over or down and over. It was the easiest part of this chapter.
Standard form is propostorious. I didnt understand. It was way to hard, It hurt my brain i dont even know how to discribe it.
I thought this chapter was fairly easy except standard. Kole is saying random blades of glory quote right now it is going to make me do good on my test. Lol i hope this test and the next couple finals wont be too hard.
December 6, 2011 at 2011-12-06T15:35:15+00:00 3:35 pm
We started out the chapter by learing rate of change and slope. The formula for slope is y2 – y1 over x2 – x1. To find the slope for a graph is rise over run. If the slope is straight up its undefined.
The next thing we learn about is slope intercept form. The y intercept is the y-cooridinate of the point where a line crosses the y-axis. A linear equation is an equation that models a linear function. The formula is y=mx+b.
THe next section were going to talk about standard form. The formula is Ax+By=C. The formula for point slope form is y-y1=m(x-x1). The most important formula is slope.
This chapter was the hardest one yet. duhhh! Its alot of formulas. The most important one is slope. I will try my best. Hopefully i do good.
December 6, 2011 at 2011-12-06T15:35:34+00:00 3:35 pm
In chapter 6 we learned about rate of change and slope. We also learned about slope-intercept form, how to apply linear functions, and standard form. The last thing we learned about was point-slope form, writing linear equations, parallel and perpendicular lines. It was kind of easy.
In section 1 we learned about rate of change and slope. Rate of change is the rate something changes it basically explains it self. Slope is ryse over run. I know you think I spelled ryse wrong but I didn’t.
After we learned all of the chapter we reveiwed all the formulas. Slope=m=y2-y1 over x2-x1. Slope-intercept=y=mx+b. Standard form=Ax+By=C. Point-slope form=y-y1=m(x-x1).
This chapter was pretty easy. But it was kind of hard at the same time. the formulas aren’t hard it just takes a while to plug every thing in and work it out. I hope I do good on the test and final.
December 6, 2011 at 2011-12-06T15:39:36+00:00 3:39 pm
in this lesson we learned the rate of change.It was simple all you have to do is divide the dependent variable by the independent variable. I used that ti find the rate of change. But that was the easy part.
Next we learned how to find a slope on a graph. All you do is use the fomula y1-y2 over x1-x2 and now you have the sope. We also learned about intecepts. It just the number that tells us where the line goes through the x and y axis.
We learned how to change two quarnants in to point slope form. All you have to do is plug in the piont quarnants. say your quarnets ar (6,-2) and your slope is 1 you plug them in to y-y1=slope (x-x1). So you answer would be y+2=1(x-6).
December 6, 2011 at 2011-12-06T15:41:26+00:00 3:41 pm
Rate of change allows you to see the relationship between two quantities that are changing. If one quantity depends on the other. Linear function is a function that graphs a line. Linear equation is an equation that models a linear function.
Slope intercept form of a linear equation is y=mx=b. Point-slope form of the equation of a nonvertical line that passes through the point. Parallel lines are lines in the same plane that never touch. Perpendicular are lines that intersect to form right angles.
I also learned how to graph equations and change them to different forms. Point-slope form equation is y-y1=m(x-x1). Standard form equation is Ax+Bx-C. Slope intecept form equation is y=mx+b.
I thought this chapter was the hardest yet. Im not sure how ill do on the test. Perpendicular lines are probably the most challenging for me. Point-Slope form was the easiest.
December 6, 2011 at 2011-12-06T16:39:03+00:00 4:39 pm
In this chapter we learned about rate of change. another thing we learend about was ride over run. We learend about point slope form.I learned about some formulas.
I learned how to find the slope of numbers and points. We also learned about the x and y interecept. We learned how to graph certain situations.how to write equations.
The class and i learned about parralell and perpendicular lines and how to tell what is what. Slope was probbly the easyiest. I learned about linear functions. We learned about T- graphs and how to use them with rate of change.
What I thought about this chapter was some stuff was easy and others were hard. I think ill do alwrite on this test. The slope was the easyiest and point slope form. other than that i liked the chapter.
December 6, 2011 at 2011-12-06T17:10:42+00:00 5:10 pm
Slope is the easiest equation to do. it is y2-y1 over x2-x1…this helps you find the slope on points. You don’t need a graph to find the slope. You use this to find the slope without a graph or if you like it better this way.
In the second lesson we learned about slope intercept form. the formula for this is y=mx+b. . b=y intercept. m=slope if given two points on a graph, you can figure out the slope, then put it in slope intercept form.
This chapter we talked about rate of change, slope, slope int. form, applying linear functions, standard form, point slope form, parallel lines, perpindicular lines. I learned alot in this chapter although we didnt get it all done. The formulas kind of mixed me up though. I am apprehensive about the test because the formulas might be a little hard but I think I got them down.
In this chapter I learned alot about how to write about graphs. I didn’t like the homework. and I hope I do good on the test!
December 6, 2011 at 2011-12-06T17:11:21+00:00 5:11 pm
I think this was the hardest chapter so far. I didnt understand most of it. I was gone a couple of days so that doesnt help. I still did okay on the review.
I found out how to find slpoe and Y-int. I already knew how to do most of that stuff though. I am pretty good at finding the slope. The Y-int is harder.
I was gone for the parellel and perpendicular lines stuff. I think it is hard. I have no idea on any of it. I will probably need help on it.
I think this chapter was the hardest so far. The test will be hard for me too. I probably should study. I dont think I will do good on the test.
December 6, 2011 at 2011-12-06T17:14:26+00:00 5:14 pm
In this chapter we learned how to apply slope, pt slope intercept form, o and i finally found out wat horizantal and vertical lines are. And we also learned wat perpindicular lines and how to graph parallel lines. we also learned about y-y and x-x is a simple way to find the slope. remember rYse over run.
We did learn about rate of change. Rate of change allows you to see the relationship between two quanities that are changing.So what you do is divide the change in the dependent variable by the change in the independent variable and that is how you get your rate of change. We use this to find it in a graph or in a equation.We also learned about finding the slpoe with using points and the formula is y1-y2 over x1-x2.
We did learned about standard form. The formula for that is Ax+By=C. First you have to find the x and y intersepts. And if you have to you can graph it. But if the equation is not set up right then u have to get the that to the side it needs to be on. In lesson 5 we learned about point-slope form and writing linear equations. The point-slope form of the equation of a nonvertical line that passes through a certian point and has a slope. Then we learnewd about parallel and perpendicular lines. Parellel lines have the same slope but diiferent y-intercept. Perpendicular lines form a upsidedown t which forms a angle.
I though this chapter was semi easy. it wasnt terribly hard but the homework wasnt the greatest i just hope i do good on th e test wedesnday. So this chapter was ok cant wait for christmas break gonna send alot of time with my family.
December 6, 2011 at 2011-12-06T17:17:45+00:00 5:17 pm
In the first section, we learned about the rate of change. We also learned about slopes. Point slope form was pretty easy, once you get it. Also, we learned Ryse over run.
In this section we also learned about slope Int. form. It has y int. and slope. this can really help out while graphing. It is not all that hard.
In this part we learned standard form. Your not supposed to have Ffrations or decimals. You use the X and Y intercepts. It was kind of hard to do this part i thought.
The test will be kind of hard. I hope to pass, but it will be difficult. I bet i will get at least a B. I think i will do okay on this test
December 6, 2011 at 2011-12-06T17:19:52+00:00 5:19 pm
In this chapter we learned alot of quiet difficult stuff. I did not like this chapter at all,not one bit. We learnded about the rate of change and alot of different forms. Some forms that we learned are point slope form y intercept form.
We also lerned about graphing some things by using the forms that we learned about. One of them was by using point solpe form heres an example. Y-Y=slope(x-x). the y-y is your y intercept point and the x is your x intercept. And you just graph by using the info.
We also learned about the slope intercept form which is Y=mx+b m is the slope and b is the y intercept. Then we learned how to get the standard form form it this part I had alot of trouble on.
This test i think is going to be hard for me cause i really messed up towrds the end of the chapter. I will probably have the mose trouble when we have to find the slope then point slope form the slope intecept form then standard form cause i always mess up on it.
December 6, 2011 at 2011-12-06T17:19:56+00:00 5:19 pm
We did chapter 6 at the end of the 1 semester. In the beginging of the this chapter it was easy. we did rate of change and slope. the slope part was easy. We all had to do this last year. Then we did slope intercept form. We did that fast. And it was really simple.
Then we applyed linear functions. This took a little thinking but whin you figer it out it was easy.Thin we did standerd form. It was varry simple. Thin came point slope form. And that was easy.
But then we did parallel and perpendicular lines. And this is hard. I still cant figer it out.. I im ging to fale this part of the ttest.i hope the teat is eas. Or im not giong to do good
December 6, 2011 at 2011-12-06T17:23:45+00:00 5:23 pm
In this chapter I have learned much. Most of the stuff that we did in this chapter was somewhat new to me. A new thing that I have learned was how to put graphing equation into standard form. The equations that I have learned before is the slope-intercept form. It was an easy chapter for me so it will hopefully be a easy test.
The main thing that is important is that we graphed some more. All that we did was put the equations into slope-intercept form.. the equation for that is y=mx+b. The m in this equation is the slope. So in the equation y =5/6x +2 the slope is 5/6.
Now that the slope-intercept is learned we can learn about the standard form. Standard form is ax+by=c. So if you have a slope-intercept form you can change it into standard form by having the x and y on the same side of the equal sign.
The that is all of the basic stuff that we learned. There is more that we have learned but I know them well. So standard form and slope-intercept form are the main important things that I think that we have gone over. It was a good chapter for my brain so this will be a challenging test too.
December 6, 2011 at 2011-12-06T17:24:23+00:00 5:24 pm
In this chapter we learned about slope. Most of it was easy, but some was hard. We learned most about slope, slope intercept, and point slope form. And we did some graphing to.
In Section 1 we learned the rate of change and slope. Finding the rate of change was hard but finding the slope wasnt. We also had to learn how to find the slope using a graph. It was easy. All you have to do is find the points and and use the slope intercept form .
In Section 2 we learn about slope intercept form. It is the easiest thing in the whole chapter. All you do is plug in the numbers to y = mx = b. I thought it was easy.
In Section 4 we learned about standard form. This was a little harder. This toole me a little longer to get the hang of. I always forget to distribute. That make me mess up alot.
I think i should do good on the test.
December 6, 2011 at 2011-12-06T17:25:58+00:00 5:25 pm
In chapter six we learned about linear equations. In section 1 I learned the rate of change and slope. The rate of change allows you to see the relationship between two numbers that are changing. slope equals vertical change over horizontal change or ryse over run.
In Section 2 I learned slope-intercept form. slope-intercept form is y=mx+b m being the slope and b being the y-intercept. Also I learned what a linear function and equation is. A linear function is a function that graphs a line. A linear equation is an equation that models a linear function.
In section 4 I learned the standard form. Standard form is Ax+By=C where A,B,and C are real numbers and A and B are not both zreo. X-intercept is the x-coordinate of the point where a line crosses the x-axis. I thought this form was easy.
In section 5 I learned point-slope form. The point-slope form of the equation of a nonvertical line that passes through the point (x1,y1) and has slope m. point-slope form looks like this y-y1=m(x-x1). I thought this chapter was the easiest for me because the forms were the easiest thing to deal with.
December 6, 2011 at 2011-12-06T17:34:33+00:00 5:34 pm
This chapter had very many lessons. They were all pretty easy. They were hard at first but once you go the hang of it they were easy. I hope i do good on this test. Good luck to everyone else.
One lesson we learned about was standard form. The equation is Ax+By=C. One example is 3x+4y=8. You can use the thumb rule do find the answer. The x=8/3 and the y=2!! This was easy.
The next lesson we learned about was point-slope form. The equation is y-y1=m(x-x1). An example is y-3=8/3(x-2). You put the slope in the m sopt. Your points go in x1 and y1. This was easy.
The last lesson is Parallel and Perpendicular lines. Parallel lines have the same slope different y intercepts. Perpendicular is negative reciprocals. This was easy also.
December 6, 2011 at 2011-12-06T17:48:14+00:00 5:48 pm
Chapter 6 teach you about Linear Equations and their graphs. 6-1 talks about the rate of change and the slope. Rate of change allows you to see the relationship between two quantities that are changing. 6-2 talks about the slope- intercept form. The slope intercept form of a linear equation is y=m x+b.
6-3 talks about Applying linear Functions. You can use these for situations like fund raising.6-4 talks about Standard form. You can use these for situations like exercising .
6-5 talks about point slope form and writing linear equations. Which is a non-vertical line that passes through the point. 6-6 Talks about parallel and perpendicular lines. You can use this if you plan a bike path.
6-7 talks about scatter plots and equations of line. You can use this to make a prediction of a line.6-8 talks about graphing absolute value equations. You can use this for graphing any type of points.
December 6, 2011 at 2011-12-06T18:06:40+00:00 6:06 pm
In Chapter 6, we learned a lot of new things. One of the first things we learned is slope which is the rate of change in a line. Slope or (m) equals y2 – y1 over x2 -x1. So if i plugged in (2,3) and (1,1) the slope would be 2 because it is -2 over -1 which makes it positive.
Then we learned about linear functions, the y-interecept, and the slope-intercept form of a line. The slope-intercept form of a line is y=mx+b. B equals the initial starting point or, y-intercept. There is also to other forms you can write a linear function which is standard form (Ax+By=C) and point slope form(y-y1=m(x-x1)).
You can also find the slope for a horizontal line and a vertical line. For horizontal line, it is just 0 and for a verticle line, it is a fraction over zero or undifined. Then we talked about parallel and perpendicular lines. The thing about them is that, for a parallel line the slope is the same but the y-intercept is different. For perpendicular lines, the slope has one and the the other slope for the other line is the negative reciprocal of the 1st line.
I thought this chapter had lots of information in it. It was for the most part easy. The easiest for me is finding the slope and doing the y-intercept form of a line. I think I will do well on the test.
December 6, 2011 at 2011-12-06T18:07:30+00:00 6:07 pm
In Chapter 6, we learned a bunch of new things. One of the first things we learned is slope which is the rate of change in a line. Slope or m equals y2 – y1 over x2 -x1. So if I plugged in (2,3) and (1,1) the slope would be 2 because it is -2 over -1 which makes it positive.
Then we learned about linear functions, the y-interecept, and the slope-intercept form of a line. The slope-intercept form of a line is y=mx+b. B equals the initial starting point or, y-intercept. There is also to other forms you can write a linear function which is standard form (Ax+By=C) and point slope form(y-y1=m(x-x1).
You can also find the slope for a horizontal line and a vertical line. For horizontal line, it is just 0 and for a verticle line, it is a fraction over zero or undifined. Then we talked about parallel and perpendicular lines. The thing about them is that, for a parallel line the slope is the same but the y-intercept is different. For perpendicular lines, the slope has one and the the other slope for the other line is the negative reciprocal of the 1st line.
I thought this chapter had lots of information in it. It was for the most part easy. The easiest for me is finding the slope and doing the y-intercept form of a line. I think I will do well on the test.
December 6, 2011 at 2011-12-06T18:12:12+00:00 6:12 pm
In this chapter we learned about Rate of Change and Slope, Slope-Intercept Form, Applying Linear Functions, Standard Form, Point-Slope Form and Writing Linear Equations, Parallel and Perpendicular Lines. Rate of change was very, extremely easy! So is finding slope, the equation is y1-y2/x1-x2. <– Obviously easy.
Slope-Intercept form is pretty easy. The equation is y=mx+b. M= Your slope, & b= your Y-Intercept. During this you always want to keep your slope in a fraction! NOT decimal. I didn't like Applying Linear Functions. Pretty complicated.
Standard Form is simple. Only thing you need to know is y and x have to be on same side. Also, no fractions or decimals. Formula is Ax+By=C. I don't like story problems with this, though.
I didn't much like this chapter. It wasn't bad at the beginning cause it was easy, but then it started to get harder. I hope I do good on this test. I also hope none of this is in our finals next week! That will suck!!!
December 6, 2011 at 2011-12-06T18:29:18+00:00 6:29 pm
In this chapter we learned about Rate of Change and Slope, Slope-Intercept Form, Applying Linear Functions, Point-Slope Form and Writing Linear Equations, Standard Form, Parallel and Perpendicular Lines.To find the rate of change you have to put the dependent variable over the independent variable. This was easy. Finding slope was easy. You just have to use the equation, y2-y1/x2-x1.
Slope-intercept form was pretty easy. The equation for it is, y=mx+b. In the equation m=slope, and b=y-intercept. Applying linear functions was hard. I really did not like it.
Standard Form was pretty easy. You have to put it in the form of, Ax+By=C. You can not have any decimals or fraction in standard form. Example of an equation in standard form is -3x+4y=8. I thought that point-slope form was really easy. All you have to do is first find the slope and then out it in point-slope form. Point-slope form is y-y=m(x-x).
Parallel and Perpendicular was okay. Parallel was easy. To tell if they are parallel lines they must have the same slope. Perpendicular lines were kinda harder for me. The slope of the line is the negative reciprocal. For example if the slope is -3/5 find it reciprocal:-5/3 then write the negative reciprocal 5/3.
This chapter was pretty easy. It was all new stuff that I learned about. I hope I do good on the test. I hope nonre of the will be on the finals!!!
December 6, 2011 at 2011-12-06T19:13:32+00:00 7:13 pm
Samantha Johnson
12-6-11
3rd hr
Chapter 6 Blog
What I learned in this chapter is parallel lines and slopes &y- intercept.
Parallel lines are lines in the same plan that never intersect. The equation of the red line is y = 1/2x + 3/2. the equation of the blue line is y = 1/2x – 1.
Ex. the equations y = 2/3x + 1 and y = 2/3x – 3 have the same slop, 2/3, and different y- intercepts. The graphs of the two equations are parallel.
Slopes the slop of a line is its rate of change.
Slope= vertical change = ryse
horizontal change =run
Formula-slope = ryse = y2-y1 , where x2-x1 not equal 0
run x2-x1
You can use any two points on a line to find its slope. You use distinguish between two points. In the diagram, (x1,y1) are the coordinates of P, and (x2,y2) are the coordinates of Q. To find the slope of , you can use the following formula.
PQ
y-intercept -two points on the line are (0,1)and (2,-3). The slope is 1-(-3) = -4
0-2 2 or -2. The y-intercept is the y- coordinates of the point where a line crosses the y- axis. Since y = -2x + 1 crosses the y – axis at (0,1) the y- intercept is 1.
If you know the slope of a line and its y-intercept, you can write the equiation of the line. The letter m refers to the slope.
December 6, 2011 at 2011-12-06T20:05:57+00:00 8:05 pm
In this chapter I learned that the rate of change allows you to see the relationship between two quantities that are the change. I did not know that the slope is rise over run. now I know that the linear function is a function that graphs a line. Direct variations are only part if the family of linear functions.
I know that parent function is the simplest equation of a function. The equation y=x or f(x)=x is the linear parent function. A linear equation is an equation that models a linear function. The variable cannot be raised to a power other than 1.
The y-intercept is the y-coordinate of the point where a line crosses the y-axis. Two sets if data have a linear relationship if the rate of change between consecutive pairs of data is the same. Parallel lines are lines in the same plan that never intersect. This is kind of confusing for me to understand. But after you get the y alone it is very easy. I wish i you have better understood this part of the section.
This chapter was more on the hard side. Its hard because sometimes i forget jhow to do something and it really frustrates me. I know i dont have to remember the formulas but they can trick you every now and then. I hope i do good on the test and the finals. But if not I will be mad because I worked so hard
December 6, 2011 at 2011-12-06T20:41:33+00:00 8:41 pm
This chapter was actually pretty neat. I only had two days that I slept in which is pretty good for me. We learned about lots of different stuff dealing with slopes. Such as, point slope equations y intercept stuff and also linear equations.
I guess I’ll talk about linear equations first. you got lots of different types like y=mx+b and y-y1=m(x-x2) and another one is Ax+By=C. You just got to plug your numbers in there
Then there is rate of change and slope. rate of change deals around how much something changed and slope is on a graph and is it ryse over run. its was cool and entertaining. i liked it
over all this chapter was all right. i give it ****** stars. im going to start doing that. its going to be out of 10 *’s. well i had fun and i hope everyone gets a good grade.
December 6, 2011 at 2011-12-06T20:47:54+00:00 8:47 pm
Standard form is Ax + By = C. This is kind of confussing for me to understand. But after you get the y alone it is very easy.I wish i you have better understood this part of the section
The main thing that is important is that we graphed some more. All that we did was put the equations into slope-intercept form.. the equation for that is y=mx+b. The m in this equation is the slope. So in the equation y =5/6x +2 the slope is 5/6.
We also learned about the slope intercept form which is Y=mx+b m is the slope and b is the y intercept. Then we learned how to get the standard form
i liked this chapter it was alot of. one of the hardest ones. i though it was kinda easy though. my favorite is y-y=m(x-x)
December 6, 2011 at 2011-12-06T20:53:01+00:00 8:53 pm
In 6-1 we learned about rate of change and slope. rate of change is the relationship between two quantities that are changing. if one quantity depends on the other then the rate of change is change in dependent cariable over the change in the independent variable. slope is rise over run or vertical change over horizontal change. the slope of a line is its rate of change.
I’ll talk about linear equations first. you got lots of different types like y=mx+b and y-y1=m(x-x2) and another one is Ax+By=C. You just got to plug your numbers in there.
The y-intercept is the y-coordinate of the point where a line crosses the y-axis. Two sets if data have a linear relationship if the rate of change between consecutive pairs of data is the same. Parallel lines are lines in the same plan that never intersect. This is kind of confusing for me to understand. But after you get the y alone it is very easy. I wish i you have better understood this part of the section.
The test will be kind of hard. I hope to pass, but it will be difficult. I bet i will get at least a C. I think i will do okay on this test.
December 6, 2011 at 2011-12-06T21:06:31+00:00 9:06 pm
This Chapter was kind of hard but i got it with a little practice. the homework was harder than most. The chapter was about, Slope, Rate of change, and all of the forms there are.
Section 1 was about Rate of change and slope. i thought this section was pretty easy. slope was probly my favorite because all you had to do was count up and over. rate of change was pretty easy too . i always forgot that the Y went on top. but i got it after a while. Section 2 was Slot-intercept form. this was pretty easy because the formula was y=mx=b. and you just pluged things in.
Section 3 was Applying Lineat Functions.i thought it was ok.. all you had to do was plot the points on the graph.Section 4 was about Standard form and the formula is Ax+Bx= C. this one i had a lil bit of trouble with but i got it in a little bit.Section 5 was about Point-slope form and Writing linear Equations. and this formula is y-y1=m( x-x1).
Section 6 was Parallel and Perpendicular lines. it was pretty easy but it was also kind of hard. i didnt get a little bit of it. section 7 was about Scatter Plots and Equations of lines. i didnt get this section very well but i think if i study hard enough i will get it in no time. Section 8 was Graphing Absolute Value.
Over all this chapter was pretty easy but i had some trouble on some stuff. i think the test will be a little hard but i will probly get a B on it. i hope i do good. Go Dawgs!
December 6, 2011 at 2011-12-06T22:45:07+00:00 10:45 pm
In Chapter 6 we learned about Rate of Change and Slope, Slope-Intercept Form, Applying Linear Functions, Standard Form, Point-Slope Form and Writing Linear Equations, and Parallel and Perpendicular Lines. For rate of change and slope you had to find the slope which is y2-y1/x2-x1 then once it’s in a fraction if it has to be simplified then you can simplify it. Basically the rate of change and slope is to show the difference between two points. Slope- intercept form is where a function graphs a line. The set up for a linear slope-intercept form would be y=mx+b. M= the slope and b would be the y-intercept.
Applying linear functions was basically to put them on graphs. Standard form was another equation set up that we learned. Ax+By=C, where A, B, and C were real numbers but A and B could not be zero. Point- slope form and writing linear equations also was a equation set up we learned. y-y1=m(x-x1) where m still equaled slope and the y1 and x1 were the points.
Parallel lines are lines that never intersect. If you need to find out if the equations are both parallel then you see if it has the same slope, but it can’t have the same y-intercept. So like if the equation was y= 2/3x+1 and the other one was y=2/3x+10 they would both be parallel to each other. Perpendicular lines are lines that intersect but only at a right angle. If the equation is y=2/3x+5 then you would have to take the reciprocal of 2/3 which would be -3/2.
Overall this chapter was pretty easy. I learned more about other set ups to equations like y=mx+b and y-y1=m(x-x1). I pretty sure that I will do just fine on the test. Definitely pass above a B+. I also can’t wait till finals! (=
December 6, 2011 at 2011-12-06T22:46:06+00:00 10:46 pm
First off in chapter 6 we learned about rate of change and slope. Rate of change is very simple you just divide the change in the dependent variable by the change in the independent variable. And to find the slope you take y-y1 over x-x1.Which is similar to rate of change.
Then we learned about slope-intercept form. Slope-intercept form is y=mx+b. Then we also learned standard form. Standard form is Ax+Bx=C.
Also in that same section we learned that when you have y= something your line on your graph will be horizontal. And when you have x= something your line on the graph will be vertical.
Next we learned about point slope form, parallel and perpendicular lines. Point slope form is y-y1=m(x-x1). Parallel lines are lines that have the same slope and different y-intercepts. And perpendicular lines have opposite reciprocals and slopes.
Overall I thought this chapter was not simple but not extremely hard either just somewhere in the middle. I think the hardest parts are perpendicular and parallel lines. And the easiest would probably be finding the slope and point-slope form. I think I will do OK on the test tomorrow !!
December 7, 2011 at 2011-12-07T02:07:03+00:00 2:07 am
Chapter 6 teach you about Linear Equations and their graphs. 6-1 talks about the rate of change and the slope. Rate of change allows you to see the relationship between two quantities that are changing. 6-2 talks about the slope- intercept form. The slope intercept form of a linear equation is y=m x+b.
you can find the slope intercept then go and put it in standard for. its not that hard. all you have to do is get y and x on teh same side then you multiply everything by the denominator. after you do that then thats in standard form and you got the right answer if you distribute right.
December 7, 2011 at 2011-12-07T04:43:07+00:00 4:43 am
In this chapter we learned a lot of new things. We learned how to find the slope. Then we learned how to change it into point slope form. Then into slope intercept form. Then into standard form.
Then we learned about things like linear functions. That’s when you do something like take a slope and a y intercept and plot it on a chart. You can plot almost anything. The y intercept is how far you go up or down. The slope is how much you travel each time.
We also learned about the rate of change. It is basically the same as slope. Sometimes it’s in a word problem. Those are hard
This chapter was hard. The test is goIng to be the hardest yet. I hope I do good on it. I’m kind of nervous.
December 7, 2011 at 2011-12-07T13:39:44+00:00 1:39 pm
over this chapter we learned that there is a lot of formulas for slope. one of them is piont-slope form. from piont slope from you can do a lot. you can find and graph a line and you can make it into other formulas. if easy to set up, all you need is the point and the slope.
next there was standard form. standard is set up like this Ax+By=C. i’ts a little confusing at first but i will get better. if you had a line and it was y=2x + 9, you would have to bring over the 2. if that 2 was a fraction or decimal you would have to multily.
now i’ll talk about lines. there are 2 types of lines. they are parralles and perpindicular. you can tell which line is which cause of the slope. if the slope is the same the lines will be parrallel. if they are not paralell then the lines will probebly perpindiucar. if the line is perpinducular then the slope most be the resiprical of the other.
over all the chapter was pretty hard. i really thought it was not fun. in this chapter the slope is inportant. without the slope you are done for. on the test i know i will bmiss a few but i’ll jsut wait and see.
December 7, 2011 at 2011-12-07T13:49:15+00:00 1:49 pm
Chapter 6 was pretty difficult. I didn’t do so good on the whole chapter. I didn’t know how to do some of the equations right at first. But i got better at them.
We learned about Change and Slope, Slope-Intercept Form, Applying Linear Functions, Point-Slope Form and Writing Linear Equations, Standard Form, Parallel and Perpendicular Lines. Finding slope was easy kinda easy. You just use the equation, y2-y1/x2-x1.
The slop intercept of X and Y was okay but having linear equations in it was hard. To tell if the lines are parallel lines they must have the same slope. Perpendicular lines were kind of harder. The slope of the line is the negative reciprocal.
Overall this chapter was pretty hard until I knew exactly what to do. I think I will do okay on this test as long as i study. I think it was the most confusing test yet.
December 7, 2011 at 2011-12-07T14:55:22+00:00 2:55 pm
The first thing we learned was rate of change. That allows you to see the relationship between two quanities that are changing. We also learned about slope. That equals rise over run.
In the next lesson we learned about linear function. It is a function that graphs a line. We also learned linear parent function. f(x)=x is that equation.
Another thing we learned about was the y-intercept. That is where a line crosses the y-axis. If you know the slope and the y-axis, you can write the equation of the line. The letter y refers to the y-intercept.
I thought this lesson was hard. I don’t get how to write the stuff in standard form. I tried to study but that didn;t work out. I hope I do good on the test.
December 7, 2011 at 2011-12-07T16:44:32+00:00 4:44 pm
In this chapter we went over a lot of stuff. Slope, slope intercept, standard form, point slope form, Parallel lines, and perpendicular lines. Finding the slope was the easiest part of these equations. I am still confused on standard form and linear problems
.
Slope intercept was very easy. The formula is y = mx + b. We have been going over this for awhile and it is very easy to me. (-2,-1) , (3,1) to find the slope of this I would take 1- -1 but two negatives equals a positive so its 1+1 over 3+2. So the slope is 2/5.
Point slope form was also very easy. The formula is y – y + mx (x – x). You plug in the slope and then plug in the points. Y+2 = 2/5 (x + 1) thats how you do that. Standard form is Ax + bx = c
December 16, 2011 at 2011-12-16T00:14:13+00:00 12:14 am
did you get the finals graded?
December 16, 2011 at 2011-12-16T04:00:37+00:00 4:00 am
Not quite, had to go see santa tonight. They will be in the computer tonight before I goto bed.
January 6, 2012 at 2012-01-06T00:47:26+00:00 12:47 am
mr.kutcher,
i made a mistake in grabbing my biology book instead of my math book. i will try to get it done before your class, but i wanted you to know that i didn’t mean to do this.
Breanna ebert